Sama caranya ya kakkk
Sudut
Penjelasan dengan langkah-langkah:
3x + 4 = 36 + x
[ 3x - x ] = 36 - 4x
2x = [ 36 - 4 ]x
2x = 32x
x = 32/2
x = 16
-----
- ↳ Sudut <ECG
= ( 3x + 4 )°
= 3(16)° + 4°
= 48° + 4°
= 52°
- ↳ Nilai <BCG
<BCG + <ECG = 180°
<BCG + 52° = 180°
<BCG = [ 180° - 52° ]
<BCG = 128°
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Diketahui dua sudut luar berseberangan sama besar
[tex]3x + 4 = x + 36 \\ 3x - x = 36 - 4 \\ 2x = 32 \\ x = \frac{32}{2} \\ x = 16[/tex]
<ECG
3x+4°
3(16°)+4°
48°+4°
52°
<BCG+<ECG=180°
<BCG+52°=180°
<BCG=180°-52°
<BCG=128°
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